S.+Lindo+Double+Displacement

{ the image is of iron ii but its iron ii in da form of an object}

Ex. Fe2S-2 + HCL-1  à H2S + Fe2Cl-1 (with charges no switchero has been done) Ex. Fe2S-2 + HCl-1  à H2S + Fe2Cl-1 with **charges** Fe2/-2S-2/2 + HCl  à H2S + Fe2/-1Cl-1/2 in **the process of switchero** FeS + HCL  à H2S + FeCl2 1 Fe 1 1 S 1 1 H 2 1 Cl 2 switchero **has happened and equation is not balanced** FeS + 2HCl  à H2S + FeCl2 1 Fe 1 1 S 1 2 H 2 2 Cl 2 equation **is balanced**
 * A.  ** Double Displacement
 * B.  ** When the metals switch places
 * C.  ** AB + CD  à  CB + AD
 * D.  **  Iron (II) Sulfide reacts with hydrochloric acid to form hydrogen sulfide gas and Iron (II) chloride
 * E.  ** 1st thing you need to do is write all the symbols for all the elements. 2nd thing you need to do is find the charges of each element. 3rd thing you need to do is do the switchero method which is when you switch the charges between elements. 4th thing you need to do is reduce so that your charges are whole numbers. HINT: hydrochloric acid is HCL-1
 * F.  ** The point of balancing an equation is that each side of the equation is equal. 1st thing you do is make sure that you change your sentence into a formula. 2nd thing you do is make a chart that shows all your elements. On the left and right hand side of each of those elements you’re going to write how much of one element is before and after the arrow. If your equation is not balanced you’re going to start plugging in coefficients or numbers before your elements until their balanced.

S. Lindo Reaction Teaching Wiki 2008