Gay-Lussac's+Law.Bertino

The Gay- Lussac Law
This law was created by Joseph Louis Gay-Lussac in 1809. His discovery was based off a prediction that as the temperature increases the pressure will do accordingly. Gay-Lussac proved this correct when he did experiments on it.

The law states that if a gas is at a fixed volume the pressure will increase accordingly to how the temperature( in Kelvin) increases. This occurs because as the temperature increases the particles begin to move faster and with a stronger impact and since they have no room to spread out it will equally increase the pressure.

The law is represented as: where: P=pressure T=temperature(Kelvin) k=constant

To solve an equation using this one would have to use the combined equation of where P1 and T1 are initial pressure and volume and P2 and V2 are a different set of pressure and temperature.

If there is a gas in a container at 2 atm when its at 55 degrees C. What would the pressure be the container was at 88 degrees C? -First you have to convert your celcius into kelvin so, 55+273= 328 degrees K and 88+273= 361 degrees K -Second you have to fill in the variables [P1=2atm, P2= missing atm, T1=328 degrees K, T2=88 degrees K] -Third you have to turn the equation so you are finding the missing variable(P2) __P1T2__ = P2 T1 -Fourth you have to fill the variables into the equation: __(2atm)(361K)__ (328K) -Calculate to get the final answer: 2.2 atm
 * An example Problem**:

This graph shows that as the temperature increases so does the pressure.

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