Boyle.Lyon

Boyles law states that when you decrease the volume a gas is contained in, then the pressure will increase. As an equation, this is expressed as ‘P1V1=P2V2’

As an example, if you double the pressure, the volume will decrease by ½.

If you have a gas under 1 atm of pressure, in a 100 mL container, what would be the pressure of that same gas in a 50 mL container?

1 atm • 100 mL = P2• 50 mL

First, you must isolate the P2. To do this, divide each side by 50 mL After doing this, this is what your equation should look like:

__1 atm • 100 mL__ = P2 50 mL

this becomes 100 mL over 50 mL, and then it is just simple division. (100÷50)

P2= 2 atm.



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