Gay-Lussac’s+Law+R.+Stacey

C. Gay-Lussac Comparing Pressure and temperature Constant: Volume Gay Lussac law: //The pressure of a fixed mass of gas at a constant volume varies directly with the Kelvin temperature. The pressure depends on the temperature. These variables also increase or decrease together.// __P1 = P____2__ - equation T1 T2

Sample Problem: The gas in a container is at a pressure of 3.00 atm at 25 C. Directions on the container warn the user not to keep it in a place where the temperature exceeds 52 C. What would the gas pressure in the container be at 52 C? The first thing to do, as always is to identify the givens and the unkown. Given: P1 of gas= 3.00 atm T1 = 25 C + 273 K = 298 K T2 52 C + 273 = 325 K Unkown: P2 of gas in atm Then, plug it in. BUT you can not jsut plug it in silly!!! you need to re-arrange the equation, because you need to find P2. So using algebra, you would You are looking to find P2, so you need to do all that is mathematically possible to un-do what is being to P2 and isolate it. __ T2P1 __ = __ P2 ____    x T2__ T1 T2  Now, this does not look friendly or clean. So, let’s fix it a bit. P2 = __T2 P1__ T1 Then, plug the values in: P2= __(325 K) (3.00 atm)__ = 3.27 atm (298 K)

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