combustion;+Z.Shea-Hill

In this reaction type, a hydrocarbon reacts with oxygen to produce water and cabon dioxide. The generic form is A+O2->CO2+2(H2O). An example is methane (CH4) and oxygen gas (O2) form cabon dioxide (CO2) and water (H2O). Methane is CH4 as the charge of Carbon is 4 so after the 'switcheroo' you have 4 hydrogen atoms. Make this into an equation by puting your reactants on the left side of the arrow and the products on the right side. CH4+O2->CO2+H2O. Now, let's balence it!
 * Combustion**

CH4+O2->CO2+H2O __1__ **C** __1__ __4__ **H** __2 2__ **O** __3__

So hydrogen and oxygen are not balenced. With coefficients, we must double the amount of 'H' on the product side. Remember; **__Don't Mess Wit Da Formulas!__**

CH4+O2->CO2+2(H2O) __1__ **C** __1__ __4__ **H** __4__ __2__ **O** __4__

Now the 'O' needs to be balenced. Double the 'O' on the reactant side.

CH4+2(O2)->CO2+2(H2O) __1__ **C** __1__ __4__ **H** __4__ __4__ **O** __4__

Yes, We have acheived equilibrium! (the equation is balenced, alright...).

good ol' water! carbon dioxide Both are created in this combustion reaction.

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