Boyle's+Law.dj

Boyle's Law states that the volume of a fixed gas varies inversely with pressure at a constant temperature. The equation to Boyle's Law looks like this: P1xV1 = P2xV2. P1 and V1 describe the initial conditions while P2 and V2 describe a different set of conditions. Given three of the four values, one can use the equation to calculate the missing value for a system at constant temperature.

A sample of oxygen gas has a volume of 150.0mL when its pressure is 0.947atm. What will the volume of the gas be at a pressure of .987atm if the temperature remains costant?
 * Example Problem:**

__Step One:__ Given: V1 of O2 = 150.0mL; P1 of O2 = 0.947; P2 of O2 = 0.987 Looking For: V2 of O2 in mL

__Step Two:__ Rearange the equation for Boyle's law in order to solve for V2 V2 = (P1V1) / P2

__Step Three:__ Substitute the given values. (0.947atm)(150.0ml) / .987atm = 144mL O2

When the pressure is increased the volume is decreased.
 * Conclusion:**

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