Gas+Laws+Teaching+Wiki+-+SGriffin+Stoich+Lesson

This page is solely dedicated to show you primitive beings how to complete a stoich problem in which you must convert kg of a substance into mL of and gas, and mL of a gas into kg of a substance.


 * kg to mL:**

(2kg N2 / 28.02g) x (71.378 mols N2 / 22.4L) = 31865.5178 mL of N2
 * The steps to this problem are follows:**
 * 1) Take the number of grams of the substance and divide it by the molar mass of the substance.
 * 2) Divide the answer by part one by 22.4L to convert the moles to liters.
 * 3) Multiply that answer to put yourself into mL.
 * 4) If you got it wrong in your puny earth mind the first time remember 1 kg is equal to 1000g


 * mL to kg (I'll use the above problem in reverse for the example):**

(31865.5178 mL of N2 / 1000) x 22.4L x 28.02g = 2000g of N2 = 2kg of N2
 * Steps:**
 * 1) Take the mL of the substance and divide it by 1000 to put it into L.
 * 2) multiply the answer to step one by 22.4L.
 * 3) Multiply step two's answer by the molar mass of the substance to give you the number of grams of the substance.
 * 4) Divide the number of grams by 1000 to put the answer into kg.